Solution.
1.
Since lithium orthophosphate contains 3 lithium ions, the amount of lithium ion substance will be equal to:
"n(Li3PO4) = \\frac{9.18}{115.79} = 0.06 \\ mole"
"n(Li^+) = n(Li3PO4) \\times 3 = 0.18 \\ mole"
2.
In order to find the mass of oxygen in lithium orthophosphate, it is necessary to find the mass fraction of the element (oxygen) and multiply it by the mass of the salt:
"w(O) = \\frac{4 \\times 16.00}{115.79} \\times 100 \\% = 55.27 \\%"
"m(O) = \\frac{9.18 \\times 55.27}{100} = 5.07 \\ g"
Answer:
1.
n(Li+) = 0.18 mole
2.
m(O) = 5.07 g
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Dear Joshua please post a new question
An unknown compound contains only C , H , and O . Combustion of 6.60 g of this compound produced 16.1 g CO2 and 6.60 g H2O . What is the empirical formula of the unknown compound?
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