if a 15.0 celcius tempature increase causes a 10.0 percent increase in the volume of a 832 ml sample of He(g) while the gas pressure is held constant what was the oridinal temperature?
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Expert's answer
2019-10-11T09:36:55-0400
Use Charle's law
"\\frac{V_1}{T_1}=\\frac{V_2}{T_2}"
"T_2 = 15+T_1"
"V_1 = 832 cm^3"
"V_2 = 832 + 0.1\\times832=915.2 cm^3"
"\\frac{832}{T_1}=\\frac{915.2}{T_1+15}"
"T_1 (K) = 150 K"
"T_2 (^\\circ C) = 150 -273 = -123 =-123^\\circ C"
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