Question

if a 15.0 celcius tempature increase causes a 10.0 percent increase in the volume of a 832 ml sample of He(g) while the gas pressure is held constant what was the oridinal temperature?

Answer 1

Use Charle's law

$$\frac{V_1}{T_1}=\frac{V_2}{T_2}$$

$T_2 = 15+T_1$

$V_1 = 832 cm^3$

$V_2 = 832 + 0.1\times832=915.2 cm^3$

$$\frac{832}{T_1}=\frac{915.2}{T_1+15}$$

$T_1 (K) = 150 K$

$T_2 (^\circ C) = 150 -273 = -123 =-123^\circ C$