A 12oz can of soft drink (assume m= 340 g) at 25 degrees Celsius is placed in a freezer where the temperature is -12 degrees Celsius. How much energy must be removed from the soft drink for it to reach this temperature?
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Expert's answer
2019-10-09T07:36:57-0400
"q=cm(T_2-T_1)"
We should make an assumption that specific heat of soft drink is the same as that of water: "c=4.186 \\frac{J}{g\\times \\circ C}"
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