If 17.0 gallons of gasohol contains 1.75 gallons of ethyl alcohol, what is the percent of alcohol in the gasohol?
The percentage of alcohol in a gasohol by volume is
"\\omega = \\frac{V(alcohol)}{V(gasohol)} \\cdot 100 \\% =\\frac{1.75 gal}{17.0gal} \\cdot 100 \\% = 10.3 \\ vol\\%"
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