Answer: 7.82 days
Solution:
"N=N_{0}\u00d7(1\/2)^{\\frac{t}{T_{1\/2}}}"
"\\ln{\\frac{N}{N_{0}}}=-{\\frac{t}{T_{1\/2}}}\u00d7\\ln2"
"t=-\\frac{\\ln{\\frac{N}{N_{0}}}\u00d7{T_{1\/2}}}{\\ln2}=-\\frac{\\ln{\\frac{C}{C_{0}}}\u00d7{T_{1\/2}}}{\\ln2}"
"t=-\\frac{\\ln{\\frac{300\\,\\mu mol\/L}{1250\\,\\mu mol\/L}}\u00d7{3.8\\,days}}{\\ln2}=7.82\\,days"
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