C6H10O4 + 2NH3 + 2H2 → C6H12N2 + 4H2O
M(C6H10O4) = 116.2 g/mol
M(C6H12N2) = 146.1 g/mol
M(NH3) = 17.0 g/mol
m(C6H10O4) = 495.5 g
mpract(C6H12N2) = 301.0 g
a) m(C6H12N2)=m(C6H10O4)*M(C6H12N2)/M(C6H10O4)=495.5g*146.1g/mol / 116.2g/mol=623.0g
b) m(NH3)=m(C6H10O4)*2*M(NH3)/M(C6H10O4)=495.5g*2*17.0g/mol / 116.2g/mol=145.0g
c) 𝜂(C6H12N2)=mpract/mtheor*100%=301.0g/623.0g*100%=48.3%
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