Answer to Question #95967 in General Chemistry for sydney spurlock

Question

When heated, KClO3
decomposes into KCl
and O2.


2KClO3⟶2KCl+3O2


If this reaction produced 77.8 g KCl,
how many grams of O2
were produced?

Answer 1

Solution.

n(KCl) = 77.8/74.5 = 1.044 mole = n(KClO₃)

1.044/2 = x/3

x = n(O₂) = 1.566 moles

m(O₂) = 1.566 * 32 = 50.112 g

Answer. 50.112 g