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Answer to Question #95889 in General Chemistry for Maddison Williams
Question #95889
What volume of 1.00 M NaOH is required to neutralize the following solution?
15.9 mL of 0.138 M phosphoric acid, H3PO4
15.9 mL of 0.138 M phosphoric acid, H3PO4
Expert's answer
15.9 x 0.138/1000= 0.0021942 moles H3PO4.
3NaOH + H3PO4 = Na3PO4 + 3H2O
3:1=x:0.0021942
x= 0.0065826 moles of NaOH.
V= n/Cm = 0.0065826/1= 0.0065826 L= 6.5826 ml.
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