Answer to Question #95854 in General Chemistry for Kyli Dean

Question

What is the maximum mass of S8 that can be produced by combining 85.0 g of each reactant?

8 SO2 + 16 H2S ⟶ 3 S8 + 16 H2O

Answer 1

We can write the reaction as

SO2 + 2H2S ⟶ (3/8)S8 + 2H2O

Now we can say from 1 mole SO2 and 2 moles of H2S 3/8 moles of S8 is formed.

85 gm SO2 = 85/64 mole SO2

85 gm H2S = 85/34 moles of H2S

For 85/34 moles of H2S, ( 85/34)*(1/2)*(3/8) moles of S8 is formed.

For 85/64 moles of SO2, (85/64)*(3/8) moles of S8 is formes.