Mass of carbon +mass of hydrogen+mass of oxygen = 14.6"\\ \\ \\ \\ \\ \\ ........(1)"
"Mass\\ of\\ C\\ in\\ CO_2=\\frac{12}{44}\\times 28.6=7.8\\ g"
"Mass\\ of\\ H\\ in \\ H_2O=\\frac{2}{18}\\times14.6=1.6222\\ g"
these carbon and hydrogen came only from the unknown sample
So,
Mass of oxygen in unknown sample = "14.6-7.8-1.6222=5.1778\\ g"
Percentage composition of oxygen in sample = "\\frac{5.1778}{14.6}\\times 100=35.464\\%"
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