Mass of carbon +mass of hydrogen+mass of oxygen = 14.6 ........(1)
Mass of C in CO2=4412×28.6=7.8 g
Mass of H in H2O=182×14.6=1.6222 g
these carbon and hydrogen came only from the unknown sample
So,
Mass of oxygen in unknown sample = 14.6−7.8−1.6222=5.1778 g
Percentage composition of oxygen in sample = 14.65.1778×100=35.464%
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