The equation of decomposition is:
"X_2CO_3\\to X_2O+CO_2"
Mass of "CO_2" formed"=1.20\\frac{g}{L}\\times2.70L=3.24g"
Moles of "CO_2" formed"=\\frac{3.24g}{44\\frac{g}{mol}}=0.0736mol"
Molar mass of "X_2CO_3=\\frac{23.8g}{0.0736mol}=323.369\\frac{g}{mol}"
So atomic mass of "X=\\frac{323.369-60}{2}=131.6845amu"
Hence quantity of metal "X=131.6845\\times0.0736=9.69g"
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