Answer to Question #95711 in General Chemistry for Juliane Duchesne

Question #95711
When 23.8 g of a group 1 carbonate was heated strongly, it decomposed to form the oxide of the group 1 element (call it element X) and 2.70 L of carbon dioxide gas, collected at 25*C. The density of carbon dioxide gas at that temperature was 1.20 g/L. Determine the quantity of the metal , X, and write the balanced equation for the reaction.
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Expert's answer
2019-10-02T08:02:49-0400

The equation of decomposition is:

X2CO3X2O+CO2X_2CO_3\to X_2O+CO_2

Mass of CO2CO_2 formed=1.20gL×2.70L=3.24g=1.20\frac{g}{L}\times2.70L=3.24g

Moles of CO2CO_2 formed=3.24g44gmol=0.0736mol=\frac{3.24g}{44\frac{g}{mol}}=0.0736mol

Molar mass of X2CO3=23.8g0.0736mol=323.369gmolX_2CO_3=\frac{23.8g}{0.0736mol}=323.369\frac{g}{mol}

So atomic mass of X=323.369602=131.6845amuX=\frac{323.369-60}{2}=131.6845amu

Hence quantity of metal X=131.6845×0.0736=9.69gX=131.6845\times0.0736=9.69g

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