Question #95672

How many grams of a
14.8% sugar solution contain 55.0 g of sugar?

Expert's answer

Mass concentration can be expressed as:


w=msugarmsolution100%w=\frac{m_{sugar}}{m_{solution}}*100\%


Thus, the mass of solution is:


msolution=msugar100%w=55.0g100%14.8%=371.6gm_{solution}=\frac{m_{sugar}*100\%}{w}=\frac{55.0g*100\%}{14.8\%}=371.6g


Finally, we can say that 371.6 g of a given solution contains 55.0 g of sugar.


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