According to the data from the conditions of the assignment, we have one significant figure in the calculations.
"n(HCl) = {m(HCl) \\over M(HCl)} = {28.8g \\over 36.5g\/mol} = 0.8 mol""n(NaOH) = {m(NaOH) \\over M(NaOH)} = {20.0g \\over 40.0g\/mol} = 0.5mol"
Based on a 1: 1 stoichiometric ratio, 0.5 mol perchloric acid should be consumed in a reaction with 0.5 mol sodium hydroxide.
Then, the amount of unreacted hydrochloric acid substance:
Accordingly, the minimum mass of the remaining acid:
"m(HCl) = n(HCl)*M(HCl) = 0.3mol*36.5g\/mol = 10.95g \\approx 11.0 g"Answer: minimum 10.95 g (about 11.0 g)
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