From the heat absorbed equation
We have
"q=mc(T_2-T_1)"
"m=2000\\ g\\\\c=4.184\\ J\\ g^{-1}\\ \\degree C^{-1}"
"T_2=369\\ K\\\\q=52700\\ \\ J"
"T_2-T_1=\\frac{q}{mc}=\\frac{52700}{2000\\times 4.184}=6.297\\ K"
"T_1=T_2-6.297=369-6.297=362.7\\ K"
Initial temprature"\\ =362.7\\ K"
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