Solution:
Radius in meters:
R=27.7ft=8.44mR=27.7 ft=8.44 mR=27.7ft=8.44m
Volume of the vat:
V=4/3(πR3)=4/3(3.14×(8.44m)3)=2518m3=2.518×106LV=4/3 (\pi R^3)=4/3 (3.14×(8.44m)^3)=2518 m^3=2.518×10^6 LV=4/3(πR3)=4/3(3.14×(8.44m)3)=2518m3=2.518×106L
Mass of fluid:
m=V×ρ=2.518×106L×2130g/L=5.363×109gm=V×\rho=2.518×10^6 L×2130 g/L=5.363×10^9 gm=V×ρ=2.518×106L×2130g/L=5.363×109g
Estimated time:
t=m/Q=5.363×109g/12005.3g/s=44.673×104s≈5.17dayst=m/Q=5.363×10^9g /12005.3g/s=44.673×10^4 s≈5.17 dayst=m/Q=5.363×109g/12005.3g/s=44.673×104s≈5.17days
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