Question

How many moles of allicin are present in 6.00 mg of this substance?

Answer 1

Molecular formula is C6H10S2O (molar mass 162.27 g/mol)

$$n=\frac{m}{M} = \frac{6.00\times 10^{-3}g}{162.27\frac{g}{mol}}=3.70\times10^{-5}mol$$