C + 2 Cl2 → CCl4
nC= 9.2 / 12 =0.767 moles.
nCl= 37.8/71= 0.532 moles.
Mol ratio = 1:2= 0.767:0.532/2.
Therefore, Cl2 is the limiting reagent.
(0.532/2) x 154 = 40.964 g (CCl4).
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