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Answer to Question #94923 in General Chemistry for Hassan Fallous
Question #94923
When 44.9 g of copper (II) sulfate pentahydrate (bluestone) is heated, all the water of hydration is removed from the compound, leaving behind pure anhydrous copper (II) sulfate. What would its dehydrated mass (in grams) be?
CuSO4•5H2O → CuSO4 + 5 H2O
Express your answer to 2 significant figures. You have 5 attempts at this question.
CuSO4•5H2O → CuSO4 + 5 H2O
Express your answer to 2 significant figures. You have 5 attempts at this question.
Expert's answer
MCuSO4= 160 g/mol
MCuSO4•5H2O= 250 g/mol
mCuSO4= 44.9*160/250= 28.74 g
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