Question

When 44.9 g of copper (II) sulfate pentahydrate (bluestone) is heated, all the water of hydration is removed from the compound, leaving behind pure anhydrous copper (II) sulfate. What would its dehydrated mass (in grams) be?

CuSO4•5H2O → CuSO4 + 5 H2O

Express your answer to 2 significant figures. You have 5 attempts at this question.

Answer 1

M_CuSO4= 160 g/mol

M_CuSO4•5H2O= 250 g/mol

m_CuSO4= 44.9*160/250= 28.74 g