n=mC6H5CHOMC6H5CHO=3.66106.12=0.034moln=\frac{m_{C_6H_5CHO}}{M_{C_6H_5CHO}}=\frac{3.66}{106.12}=0.034moln=MC6H5CHOmC6H5CHO=106.123.66=0.034mol
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