Question

A 0.86 L sample of nitrogen gas is at a temperature of 45.0°C. If the volume decreases to 0.56 L what is the temperature of the gas?

Answer 1

$V_1/T_1=V_2/T_2$

$T_2=\frac{V_2·T_1}{V_1}=\frac{0.56·(273.15+45.0)}{0.86}=$ 207.2K=-66.0C

Answer:-66.0C