Question

25 mL of a 0.1111 M NaCl solution is pipetted into a clean dry 250 mL beaker. To this 25 mL of deionized water is also pipetted.
The concentration of NaCl in the 250 mL beaker is 0.1111 M. True or false?

Answer 1

No. It is not true.

Cm=n/V. n=Cm x V = 0.1111 x 0.025 =0.0027775 moles.

Cm = 0.0027775 / 0.05 = 0.05555 M