The molar mass of H2S is:
M(H2S)=2∗M(H)+M(S)=2∗1g/mol+32g/mol=34g/molM(H_2S)=2*M(H)+M(S)=2*1g/mol+32g/mol=34g/molM(H2S)=2∗M(H)+M(S)=2∗1g/mol+32g/mol=34g/mol
Thus, the amount in moles of 1.47 g of H2S:
n(H2S)=m(H2S)M(H2S)=1.47g34g/mol=0.043moln(H_2S)=\frac{m(H_2S)}{M(H_2S)}=\frac{1.47g}{34g/mol}=0.043moln(H2S)=M(H2S)m(H2S)=34g/mol1.47g=0.043mol
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