The molar mass of H2S is:
"M(H_2S)=2*M(H)+M(S)=2*1g\/mol+32g\/mol=34g\/mol"
Thus, the amount in moles of 1.47 g of H2S:
"n(H_2S)=\\frac{m(H_2S)}{M(H_2S)}=\\frac{1.47g}{34g\/mol}=0.043mol"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment