Question

25ml of a vinegar solution is titrated with 40ml 0f 0.1 M NaOH solution.How many moles of NaOH were used and how many moles of acetic acid were reacted

Answer 1

$CH_3COOH+NaOH=CH_3COONa+H_2O$

$v_{CH_3COOH}=v_{NaOH}=V_{NaOH}·C_{NaOH}=0.04·0.1=0.004mol$

Answer:$v_{CH_3COOH}=v_{NaOH}=0.004mol$