dT = Kb * b * i
Kb for water = 0.513
b = 0.5/(0.513 * 2) = 0.48 (mol/kg)
b = n*i/m
n(NaCl) = b*m = 0.48 * 1.1 = 0.53 (mol)
m(NaCl) = n * M = 0.53 * 58.5 = 31 (g)
Answer: m(NaCl) = 31 g
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