Question #94333
A tree 33 m tall and 0.55 m in diameter at its base produces about 67000 L of oxygen per year. A person who exercises vigorously several hours a day might take in about 22 m of all per day. How many trees are needed to provide oxygen to 900 people breathing?
1
Expert's answer
2019-09-12T03:33:33-0400

Person consumes 22m322m^3 air per day=0.2×22=4.4m3 O20.2\times 22=4.4m^3\ O_2\\

 air contains 20 percentage of oxygen\because\ air\ contains\ 20\ percentage \ of \ oxygen

900 people will need 4.4×900=3960m3 O24.4\times 900=3960m^3\ O_2 per day

total oxygen required per year = 3960×365=1445400m3 O23960\times 365=1445400m^3\ O_2

Amount of Oxygen given by 1 tree per year = 67000 l=67 m367000\ l=67\ m^3

Total no. of trees required = 144540067=21573.134\frac{1445400}{67}=21573.134

So, nearly 21573 trees will be required.



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