Answer to Question #94002 in General Chemistry for Divina

Question

Given that E° = 0.52V for the reduction Cu^+ (aq) + e^- —> Cu (s), calculate E°, ∆G° and K for the following reaction at 25°C.

2Cu^+ (aq) —> Cu ^2+ (aq) + Cu(s)

Answer 1

We have the formula:

E^o_cell=E^o_cathode−E^o_anode E^o_cell=0.520−0.159 E^o_cell=0.361V E_cello=E_cathode^o−E_anode^o E_cello=0.520−0.159 E_cello=0.361V

We have the formula,

ΔG^o=−nFE^o ΔG^o=−(1)(96500)(0.361)ΔG^o=−34836.5J ΔG^o=−nFE^o ΔG^o=−(1)(96500)(0.361) ΔGo=−34836.5J

Now,

We have,

ΔG^o=−2.3022nRTlogK−34836.5=−(2.303)(8.314)(1)(298)logKK=1.27×10⁶