Answer to Question #93958 in General Chemistry for Kylie

Question

In an experiment, a student
found that the molarity of acetic acid in a vinegar was 0.640 mol/L.

(a) Calculate the acetic acid in g/L.
(b) What is the concentration of acetic acid in g per 100 mL of vinegar?
(c) What, therefore, is the weight by volume percentage (w/v %) of
acetic acid in the vinegar?
(d) Is the product information on the label correct if the label states
that the vinegar is 4 w/v %?

Answer 1

(a)c(acetic acid) = 60g/mol * 0.640 mol/L = 38.4 g/L

(b)38.4 g/L*0.1L = 3.84 g per 100 mL.

(c) w(acetic acid)= 3.84g/100g*100%= 3.84%

(d) information is incorrect