Answer to Question #93671 in General Chemistry for daniela

Question

At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L. What volume would the same amount of gas occupy at the same pressure and 80 ∘C ?
Express your answer with the appropriate units.

Answer 1

From ideal gas equation

We know that

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Where,$P_1,V_1,T_1,$ are initial pressure,initial volume and initial temprature respectively

and$P_2,V_2,T_2,$ are final pressure,final volume and final tempreture respectively

Now,

$V_2=\frac{P_1V_1T_2}{P_2T_1}$

$P_1=101325pascals$

$V_1=0.0224m^3$

$T_1=273.15K$

$P_2=P_1$

$T_2=253.15K$

So, $V_2=\frac{101325\times0.0224\times 253.15}{101325\times 273.15}=0.02076m^3$

Volume occupied at $80\degree C$ and same pressure will be $20.76l$