Question #93645

What is the molarity of a solution made by dissolving 5.25 g of potassium
hydrogen phthalate in distilled water and making it up to 250 mL with
distilled water in a volumetric flask?

Expert's answer

First of all find the amount of potassium hydrogen phthalate:


ν=m/M\nu = m/M

Find molar mass of potassium hydrogen phthalate (KHC8H4O4):


M=39+1+(812)+4+(416)=204(g/mol)M = 39 + 1 + (8*12) + 4 + (4*16) = 204 (g/mol)

ν=5.25/204=0.0257(mol)\nu = 5.25/204 = 0.0257 (mol)


Find the molarity of the solution, if there is 0.0257 mol in 250 ml:

Cm=ν/VC_m = \nu/V

Cm=0.0257/0.25=0.1028(mol/L)C_m = 0.0257/0.25 = 0.1028 (mol/L)


Answer: the molarity of the potassium hydrogen phthalate solution is 0.1028 mol/L.

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