First of all find the amount of potassium hydrogen phthalate:
Find molar mass of potassium hydrogen phthalate (KHC8H4O4):
"M = 39 + 1 + (8*12) + 4 + (4*16) = 204 (g\/mol)"
"\\nu = 5.25\/204 = 0.0257 (mol)"
Find the molarity of the solution, if there is 0.0257 mol in 250 ml:
"C_m = \\nu\/V"
"C_m = 0.0257\/0.25 = 0.1028 (mol\/L)"
Answer: the molarity of the potassium hydrogen phthalate solution is 0.1028 mol/L.
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