Question

A graduated cylinder contains 155mL of water. a 15.0 g piece of iron and a 20.0 g piece of lead are added. What is the new water level?

Answer 1

density of iron: d(Fe)=7.9 g/cm³

density of lead: d(Pb)=11.3 g/cm³

$V(add)=V(Fe)+V(Pb)=m(Fe)/d(Fe)+m(Pb)/d(Pb)=15.0/7.9+20.0/11.3=3.7mL$

$V(new)=V(water)+V(add)=155+3.7=158.7mL$