C8H6O4 it is the answer
Solution
Molecular weigh = 41.5/ 0.25 =166 g/mole
CxHyOz combustion to CO2 and H2O
Mole of CO2 = 41.98*10^-3/44= 0.00095
Mole of H2O = 6.95*10^-3/18= 0.00036
Mole of CxHyOz = 0.00012
Because Cx -> CO2 and
Hy-> H2O, that is why,
X= 0.00095/0.00012= 8
Y= 0.00036*2/0.00012= 6
Z= (166- 8*12- 6*1)/16=4
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