Answer to Question #93395 in General Chemistry for Joyce Villanueva

Question #93395

A person weighing 75.0 kg (165 lbs) runs a course at 1.78 m/s (4.00 mph). What is the person’s kinetic energy?

Expert's answer

E"_K" = "\\frac{1}{2}" (75.0kg)(1.78"\\frac{m}{s}") "^2"

= 119 "\\frac{ kg.m^2 \n2\n }{s^2 \n}" = 119J

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