Answer to Question #93395 in General Chemistry for Joyce Villanueva

Question

A person weighing 75.0 kg (165 lbs) runs a course at 1.78 m/s (4.00 mph). What is the person’s kinetic energy?

Answer 1

E$_K$ = $\frac{1}{2}$ (75.0kg)(1.78$\frac{m}{s}$) $^2$

= 119 $\frac{ kg.m^2 2 }{s^2 }$ = 119J