Question

in order to make 0.100 L of a 6.0 M solution of H2SO4, how many grams of H2SO4 must be weighed out? Assume a molar mass of 98.1 g/mol and give the answer to 2 significant figures.

Answer 1

Let's found how many moles of H₂SO₄ are there in 0.1L of 6.0M solution:

$$\nu = C * V = 6 * 0.1 = 0.6 (moles)$$

Find the mass of 0.6 moles of H₂SO₄:

$$m = \nu * M = 0.6 * 98.1 = 59 (g)$$

Answer: 59 g of H₂SO₄ must be weighed out in order to make 0.100 L of a 6.0 M solution.