For the given reaction
3A(g)+B(g)⇌2C(g)+2D(g)3A_{(g)}+B_{(g)} \rightleftharpoons 2C_{(g)} + 2D_{(g)}3A(g)+B(g)⇌2C(g)+2D(g)
equilibrium-constant expression will be
Kc=[C]2⋅[D]2[A]3⋅[B]K_c=\frac{[C]^2 \cdot [D]^2}{[A]^3 \cdot [B]}Kc=[A]3⋅[B][C]2⋅[D]2
where [A], [B], [C], and [D] are molar concentrations of A, B, C, and D respectively.
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