Answer to Question #92004 in General Chemistry for jimbo

Question #92004
For the reaction
2H2O(g)↽−−⇀2H2(g)+O2(g)
the equilibrium concentrations were found to be
[H2O]=0.250 M,[H2]=0.350 M,and [O2]=0.750 M.
What is the equilibrium constant for this reaction?
1
Expert's answer
2019-07-29T04:29:54-0400

For the reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) the equilibrium concentrations were found to be [H2O]=0.250 M,[H2]=0.350 M,and [O2]=0.750 M.

What is the equilibrium constant for this reaction?

Solution.

K=([H2]2[O2])/([H2O]2)=0.35020.750/0,2502=1,47MK=([H2]^2*[O2])/([H2O]^2)=0.350^2*0.750/0,250^2=1,47 M

Answer K=1,47 M



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