Question

For the reaction
2H2O(g)↽−−⇀2H2(g)+O2(g)
the equilibrium concentrations were found to be
[H2O]=0.250 M,[H2]=0.350 M,and [O2]=0.750 M.
What is the equilibrium constant for this reaction?

Answer 1

For the reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) the equilibrium concentrations were found to be [H2O]=0.250 M,[H2]=0.350 M,and [O2]=0.750 M.

What is the equilibrium constant for this reaction?

Solution.

$K=([H2]^2*[O2])/([H2O]^2)=0.350^2*0.750/0,250^2=1,47 M$

Answer K=1,47 M