Question #91881
If given 0.0543 kg of calcium nitrate to dissolve with water to 0.355L, what would be the concentration
1
Expert's answer
2019-07-23T07:52:47-0400
c=54.3g164.088g/mol∗0.355L=0.932mol/Lc= \dfrac{54.3g}{164.088g/mol*0.355L }=0.932mol/L


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