Question #91844
How many atoms of phosphorus are in 4.10 mol of copper(II) phosphate?
1
Expert's answer
2019-07-22T07:23:04-0400

N atoms “P”= 4.1∗6.02∗1023∗2=4.94∗10244.1*6.02*10^{23}*2=4.94*10^{24}


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