Answer to Question #91585 in General Chemistry for Robyn

Question #91585
6g of metal M reacts completely with 23.66g of Chlorine to form 29.66g of the metallic chloride. find the empirical formula of the metallic chloride. (M=27, Cl=35.5)
1
Expert's answer
2019-07-11T03:10:26-0400

According to the law of equivalents:


"m(M) : m(Cl_2) = M_{eq}(M) : M_{eq}(Cl_2)""M_{eq} (Cl_2) = m(Cl_2)\/z = 71\/2 = 35.5 mol""6 : 23.66 = M_{eq}(M) : 35.5""M_{eq}(M) = 9 g\/mol"

If the molar mass of the metal element is 27, then the equivalence number:

"z(M) = 27\/9 = 3"

"z(Cl_2) = 2"

"z(Cl) = 1"

Then the empirical formula of metal chloride:


"MCl_3"

Answer: MCl3

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