Answer to Question #91417 in General Chemistry for liv

Question

A student was studying the balanced reaction: CS2+3O2=CO2+2SO2
Answer the following questions if this reaction started with 4 molecules of CS2 and 9 molecules of O2.
what chemical in this balanced reaction is the limiting reactant?
How many molecules of CO2 would be made on a complete reaction?
how many molecules of the SO2 would be made in a complete reaction?
how many molecules of CS2 would remain at the end of a complete reaction?
how many molecules of O2 would remain at the end of a complete reaction?

Answer 1

1) In this reaction ratio of reagents:

$n(CS_2) : 3n(O_2)$

Respectively if  this reaction started with 4 molecules of CS₂ and 9 molecules of O₂ ratio (CS₂) : (O₂):

$4 : 9$

$1 : 2.25$

Respectively the limiting reactant is O₂.

2)

$3n(O_2) : n(CO_2)$ $n(CO_2) = n(O_2)/3 = 9/3 = 3 (moleculas)$

3)

$3n(O_2) : 2n(SO_2)$ $n(SO_2) = (n(O_2)*2)/3 = (9*2)/3 = 6 (moleculas)$

4)

$n(CS_2) = n(O_2)/3 = 9/3 = 3 (moleculas)$

If at the beginning of the reaction the molecules CS₂ was 4 , and 3 responded, respectively, after the reaction, 1 molecule CS₂ remained

5) All molecules O₂ reacted. After the reaction, not a single molecule O₂.

Answer: 1) O₂; 2) 3 moleculas; 3) 6 moleculas; 4) 3 moleculas; 5) not a single molecule.

what chemical in this balanced reaction is the limiting reactant?

Answer - O2

How many molecules of CO2 would be made on a complete reaction?

Answer - 3 molecules CO2

how many molecules of the SO2 would be made in a complete reaction?

Answer - 6 molecules SO2

how many molecules of CS2 would remain at the end of a complete reaction?

Answer - 1 molecule CS2

how many molecules of O2 would remain at the end of a complete reaction?

Answer - 0 molecules O2