2KClO3"\\to" 2KCl+3O2
"m(O2)=\\dfrac{11.0g*3*32g\/mol}{122.55g\/mol*2}=4.31g"
"V=m*R*T\/M*P=\\dfrac{4.31*62.364L*torr\/\u041a^{-1}*mol^{-1}*303.15\u041a}{32g\/mol*717.2torr}=3.55L"
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