n(CH3CH2OH)=0.762g46.07g/mol=0.01654molesn(CH3CH2OH)=\dfrac{0.762g}{46.07g/mol}=0.01654molesn(CH3CH2OH)=46.07g/mol0.762g=0.01654moles
n(CH3CH2OH)=n(CH3COOH)=0.01654molesn(CH3CH2OH)=n(CH3COOH)=0.01654molesn(CH3CH2OH)=n(CH3COOH)=0.01654moles
m(CH3COOH)=0.01654moles∗60.05g/mol=0.993gm(CH3COOH)=0.01654moles*60.05g/mol=0.993gm(CH3COOH)=0.01654moles∗60.05g/mol=0.993g
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment