Question

If the rate of appearance of oxygen over change in time is 6.0*10^-5ms^-1 at a particular instance.what is the rate of dissappearance of Oxygen3 at the same time.

Answer 1

Balanced chemical equation is:

$$2O_3(g)\rightarrow 3O_2(g)$$

$$Rate = -\frac{1}{2}\times \frac{\Delta [O_3]}{\Delta t} = \frac{1}{3}\times \frac{\Delta [O_2]}{\Delta t}$$

Express yje rate of dissaperatnce of O₃ from this equation:

$$-\frac{\Delta [O_3]}{\Delta t} = \frac{2}{3}\times \frac{\Delta [O_2]}{\Delta t} = \frac{2}{3}\times (6.0\times 10^{-5}\frac{M}{s})= 4.0\times 10^{-5} \frac{M}{s}$$