The mass of carbon in the sample is the same as the mass of carbon in the carbon dioxide produced.
n(CO2)=m(CO2)M(CO2)=m(C in CO2)M(C)n(CO_2)=\frac{m(CO_2)}{M(CO_2)}=\frac{m(C \ in \ CO_2)}{M(C)}n(CO2)=M(CO2)m(CO2)=M(C)m(C in CO2)
m(C in CO2)=m(CO2)M(C)M(CO2)=0.22g⋅12gmol44gmol=0.06gm(C \ in \ CO_2) = m(CO_2)\frac{M(C)}{M(CO_2)}=0.22g \cdot \frac{12\frac{g}{mol}}{44\frac{g}{mol}}=0.06gm(C in CO2)=m(CO2)M(CO2)M(C)=0.22g⋅44molg12molg=0.06g
Thus the mass of carbon in the sample is 0.06g
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