The mass of carbon in the sample is the same as the mass of carbon in the carbon dioxide produced.
"n(CO_2)=\\frac{m(CO_2)}{M(CO_2)}=\\frac{m(C \\ in \\ CO_2)}{M(C)}"
"m(C \\ in \\ CO_2) = m(CO_2)\\frac{M(C)}{M(CO_2)}=0.22g \\cdot \\frac{12\\frac{g}{mol}}{44\\frac{g}{mol}}=0.06g"
Thus the mass of carbon in the sample is 0.06g
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