Question #90639
what mass of copper (ii) oxide is required to produce 12.8 g of copper?
1
Expert's answer
2019-06-07T12:56:45-0400

m(CuO)=m(Cu)∗M(CuO)M(Cu)=12.8g∗79.55g/mol63.55g/mol=16.02gm(CuO)=\dfrac{m(Cu)*M(CuO)}{M(Cu)}=\dfrac{12.8g*79.55g/mol}{63.55g/mol}=16.02g


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