2.5 atm = 253313 Pa
The following reaction occurs:
"Ca \\ + \\ 2HCl \\ = \\ CaCl_2 \\ + \\ H_2\\uparrow"
First calculating amount of calcium given:
"n(Ca)=\\frac{m(Ca)}{M(Ca)}=\\frac{20.0g}{40\\frac{g}{mol}}=0.5mol"
The same amount of hydrogen gas will be evolved: n(H2)=n(Ca)=0.5 mol
Using ideal gas law pV=nRT we can find volume of the hydrogen:
"V(H_2)=\\frac{n(H_2)RT}{p(H_2)}=\\frac{0.5mol \\cdot 8.314 \\frac{J}{mol \\cdot K} \\cdot 350K}{253313Pa}=0.00574 m^3=5.74L"
Comments
Leave a comment