From equation for molar concentration "c=\\frac{n}{V}" we can found volume of 1.93M solution containing 71 moles of KI:
"V=\\frac{n}{c}=\\frac{71 mol}{1.93\\frac{mol}{L}}=36.8L"
Taking into account that the density of 1.93M solution is about 1.22 kg/L (tabulated data), mass of the solution can be found:
"m(solution)=d \\cdot V=1.22\\frac{kg}{L} \\cdot 36.8L = 44.9 kg"
Thus the mass of solvent can be calculated:
"m(solvent)=m(solution)-m(KI)=m(solution)-n(KI) \\cdot M(KI)=44.9kg-71mol \\cdot 166 \\times 10^{-3} \\frac{kg}{mol}= 44.9kg-11.8kg=33.1kg"
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