The Stoichiometric equation for the reaction is
2NH 3 + 6F 2 → 6HF + 2NF 3
Thus according to above equation 2 moles of NH 3 reacts with 6 moles of fluorine to form 6 moles
of HF
Moles of NH 3 = (243/17) = 14.29 moles
2 moles of NH 3 = 6 moles of HF
1 mole of NH 3 = 3 moles of HF
14.29 moles of NH 3 = 3*14.29 mole of HF
Thus 42.87 moles of HF are produced.
Comments
Leave a comment