Molar concentration can be determined by the following equation:
"c=\\frac {n}{V}"
, where n - amount in moles, V - volume of solution in liters.
"n=\\frac{m}{M}"
, where m - mass of powdered drink mix, and M - molar mass of powdered drink mix.
Thus, "c=\\frac{m}{M \\cdot V}"
"M(C_{12}H_{22}O_{11})=12 \\cdot 12 \\frac{g}{mol} + 22 \\cdot 1 \\frac{g}{mol} + 11 \\cdot 16 \\frac{g}{mol} = 342 \\frac{g}{mol}"
"m = M \\cdot V \\cdot c = 342 \\frac {g}{mol} \\cdot 0.1 L \\cdot 1.0 \\frac{mol}{L} = 34.2 g"
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