Plot the logarithm of the initial rate, log v0, against log[I]0 for a given concentration of Ar, and, separately, against log[Ar]0 for a given concentration of I. The slopes of the two lines are the orders of reaction with respect to I and Ar, respectively. The intercepts with the vertical axis give log k′r and, by using eqn 2.10, kr. The plots are shown in Fig. 1.
Fig. 1a. The plot of log v0 against log[I]0 for a given [Ar]0
Fig. 1b. The plot of log v0 against log[Ar]0 for a given [I]0
The slopes are 2 and 1, respectively, so the (initial) rate law is v0 = kr[I]02[Ar]0. This rate law signifies that the reaction is second-order in [I], first-order in [Ar], and third-order overall. The intercept corresponds to kr = 9 × 109 mol−2 dm6 s−1.
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