Question

Calculate the total number of ions in one gram of Na2HPO4.

Answer 1

$n(Na2HPO4)=\dfrac{1g}{141,96g/mol}=0.007moles$

$N(Na2HPO4)=0.007moles*6.02*10^{23}=4.214*10^{21}molecules$

Na₂HPO₄$\leftrightarrow$ 2Na⁺+H⁺+PO₄ ^3-

total number of ions=$4.214*10^{21}*4=1.69*10^{22}$